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Alex Ar [27]
3 years ago
14

HELP NEED HELP ! 1 + 1 = ?

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

2  ;-;

Step-by-step explanation:

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Find the quotient 4/12 divided by 4/12
Natali5045456 [20]

Answer:

1

Step-by-step explanation:

Keep-Change-Flip

4/12 (keep) × (change) 12/4 (flip)

4/12 × 12/4

4 × 12 = 48

12 × 4 = 48

48/48 = 1

3 0
3 years ago
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HELP PLS
kiruha [24]
-20 is the answer. Your welcome I might have gotten it wrong but at leAst I tried
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3 years ago
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BRAINLIEST!!!
Nutka1998 [239]

Answer:

\frac{35}{48}

Step-by-step explanation:

Probability:Probability=\frac{favourable\ outcome}{total\ outcome}

Probability of NOT 6:

Total\ outcomes=\{1,2,3,4,5,6\}\\\\Number\ of\ total\ outcomes=6\\\\Favourable\ Outcomes= NOT\ 6=\{1,2,3,4,5\}\\\\Number\ of\ favourable\ outcomes=5\\\\P(NOT\ 6)=\frac{5}{6}

Probability of NOT H:

Total\ outcomes=\{A,B,C,D,E,F,G,H\}\\\\Number\ of\ total\ outcomes=8\\\\Favourable\ Outcomes= NOT\ H=\{A,B,C,D,E,F,G\}\\\\Number\ of\ favourable\ outcomes=7\\\\P(NOT\ H)=\frac{7}{8}

Probability of NOT 6 and NOT H:

Both\ events\ are\ independent\\\\P(NOT\ 6\ and\ NOT\ H)=P(NOT\ 6)\times P(NOT\ H)\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{5}{6}\times \frac{7}{8}\\\\P(NOT\ 6\ and\ NOT\ H)=\frac{35}{48}

6 0
3 years ago
for edmentum or plato how do you make a chart or graph larger. not enough rows for my checkbook assignment ​
mixas84 [53]

here hope this helps!

Step-by-step explanation:

8 0
3 years ago
3x-(2x-1)=7x-(3*5x)+(-x+24)
Paraphin [41]

Answer:

\boxed{\boxed{\sf x=\frac{23}{10}}\: \sf or \:\boxed{x=2.3}}

_________________

\boxed{\sf Step\: By\:Step:- }

\sf 3x-\left(2x-1\right)=7x-\left(3\times \:5x\right)+\left(-x+24\right)

<u>Remove the parentheses:</u>

\to\sf 3x-\left(2x-1\right)=7x-3\times \:5x-x+24

<u>Combine like terms:</u>

\sf ^*7x-x=6x

\to\sf 3x-\left(2x-1\right)=6x-3\times \:5x+24

<u>Multiply 3 and 5x = 15x:-</u>

\to\sf 3x-\left(2x-1\right)=6x-15x+24

<u>Combine like terms:</u>

\sf ^*6x-15x=-9x

\to\sf 3x-\left(2x-1\right)=-9x+24

<u>Expand: 3x-(2x-1)= x+1</u>

\to\sf x+1=-9x+24

<u>Subtract 1 from both sides:</u>

\to\sf x+1-1=-9x+24-1

\to\sf x=-9x+23

<u>Add 9x to both sides:</u>

\to\sf x+9x=-9x+23+9x

\to\sf 10x=23

<u>Divide both sides by 10:</u>

\to\sf \cfrac{10x}{10}=\cfrac{23}{10}

\to\sf x=\cfrac{23}{10}

<u>________________________________</u>

3 0
3 years ago
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