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Alex Ar [27]
3 years ago
14

HELP NEED HELP ! 1 + 1 = ?

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

2  ;-;

Step-by-step explanation:

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HELPPPPP
OlgaM077 [116]

Answer:

Point on Midline (0,3)

Maximum (9π/2,3)

Minimum (-9π/2,-3)

Step-by-step explanation:

in the given sine function which is in the form of f(x) = a sin(bx+c) +d

a = amplitude

period = frequency = 18π

Therefore b = 2π/18π = 1/9

Y intercept = vertical shift = 3

Horizontal shift = d = 0

Therefore the sine function will be

f(x) = 6 sin(x/9) + 3

Now first point on the midline is (0,3)

Second point is maximum (9π/2,9)

Third point be a minimum value ( -9π/2,-3)

7 0
2 years ago
What is 1,376 x 6 equal to
Arte-miy333 [17]

Answer:

8256

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Distributive property of<br> 36+ 9y
vaieri [72.5K]
Find the greatest common factor (GCF)
in this case it would be 9

divide each term by the GCF
36 / 9 = 4
9y / 9 = y

put the two "new" terms in parenthesis and the GCF in front of it
9 (4 + y)
it could also be 9 (y + 4) because of Commutative Property of Addition
6 0
3 years ago
Read 2 more answers
Dr. Blumen invested $5,000 part of it was invested in bonds at a rate of 6% in the rest was invested in a money market at the ra
abruzzese [7]
So... let's say the amounts invested were "a" at 6% and "b" at 7.5%.

ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.

now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus a + b = 5000

and the interest yielded was 337.50, thus 0.06a + 0.075b = 337.50

thus    \bf \begin{cases}&#10;a+b=5000\implies \boxed{b}=5000-a\\&#10;0.06a+0.075b=337.50\\&#10;----------\\&#10;0.06a+0.075\left( \boxed{5000-a} \right)=337.50&#10;\end{cases}

solve for "a", to see how much was invested at 6%.

what about "b"?  well, b = 5000 - a.
6 0
3 years ago
Read 2 more answers
Which equation matches this graph?
Harman [31]

Answer:

y = 4"x +2

Step-by-step explanation:

We choose negative 4 because the graph lies below the asymptote and we chose positive 2 because the horizontal asymptote is on the positive section of the y axis

6 0
2 years ago
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