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Natasha_Volkova [10]
2 years ago
12

The graph of g(x)=(0.75)x+2 is shown.

Mathematics
1 answer:
Andrei [34K]2 years ago
6 0

we are given

f(x)=(0.75)^x+2

For finding asymptote , we can find limit

\lim_{x \to \infty} f(x)= \lim_{x \to \infty}((0.75)^x+2)

\lim_{x \to \infty} f(x)= \lim_{x \to \infty} (0.75)^x+\lim_{x \to \infty} 2)

now, we can solve it

\lim_{x \to \infty} f(x)= 0+2

\lim_{x \to \infty} f(x)= 2

so, horizontal asymptote is

y= 2.............Answer

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(used parentheses due to "forbidden language")
pishuonlain [190]

Answer:

Segment GD is half the length of segment HC​ ⇒ answer D

Step-by-step explanation:

* Look to the attached file

Download docx
7 0
3 years ago
Which doubles fact helps you solve 8+7=15? Write the number sentence.
12345 [234]
8 + 8 = 16
16 - 1 = 15

or

7 + 7 = 14
14+1 = 15
7 0
3 years ago
Read 2 more answers
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
2 years ago
The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar
marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2

Substituting this in the section formula

R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)  

To simplifying the expression, we get

\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)

\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)

⇒ R(x,y) = R(–3,4)  

Hence, the coordinates of point R is (–3, 4).

6 0
3 years ago
Need help asap pls :)
pogonyaev

Answer:

See explanation below.

Step-by-step explanation:

First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10

Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115

Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.

Angle 5 = 10

Angle 4 = 55

Angle 6 = 115

Now we can find angle 8. 180-115=65. Angle 8 = 65

Angle 11 = 65

Angle 12 = 115

10+115=125 Angle 10 = 125

180-125 = 55 Angle 9 = 55

Angle 14 = 55

Angle 13 = 125

7 0
2 years ago
Read 2 more answers
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