Find the midpoint of the segment with the given endpoints. (9,9) and (-1,- 3)

Mathematics

1 answer:

GenaCL600 [577]3 years ago

8 0

Answer: (4, 3)

Step-by-step explanation:

The formula for coordinate of the mid point is given as :

Mid point = ( $\frac{x_{2}+x_{1}}{2}$ , $\frac{y_{2}+y_{1}}{2}$ )

$x_{1}$ = 9

$x_{2}$ = -1

$y_{1}$ = 9

$y_{2}$ = -3

Substituting the values into the formula , we have :

Mid-point = ( $\frac{-1+9}{2}$ , $\frac{-3+9}{2}$ )

Mid-point = ( $\frac{8}{2}$ , $\frac{6}{2}$ )

Mid - point = ( 4 , 3)

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The weight of an organ in adult males has a bell-shaped distribution with a mean of 310 grams and a standard deviation of 25 gra

Shkiper50 [21]

Answer:

About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be About 68% of organs will be between 300 grams and 320 grams, About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ−σ=320−20=300grams

\rm \mu+\sigma = 320+20=320 \; gramsμ+σ=320+20=320grams