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Mkey [24]
3 years ago
9

Part A: Joseph runs 212 miles on Monday. Each day after that, he runs the same 113 mile route every morning. His goal is to run

at least 6 miles by the end of the week. Which inequality represents the least number of days after Monday that Joseph needs to run to reach his goal?
Part B: What is the least number of days after Monday that Joseph needs to run to reach his goal?

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0

Answer:

Part A - C, 2 1/2 + 1 1/3 x <u>></u> 6

Part B - number of days = 3

Natalija [7]3 years ago
5 0

Answer:   325

Step-by-step explanation        212 + 113 = 325

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Write a system of equations to describe the situation below, solve using elimination, and fill in
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Answer:  Child is $1 and Adult is $3, per person.

Step-by-step explanation:

We have two unknowns, so we need at least two equations.  Let C and A stand for the price of a ticket for a child and an adult, respectively.

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Tuesday:  24C + 26A = $102

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24C + 26A = $102

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Now use this expression for C in the first equation

16C + 42A = $142

16(($102 - 26A)/24) + 42A = $142

16(($102 - 26A)/24) + 42A = $142

(1632 - 416A)/24 + 42A = $142

(68 - 17.3333A + 42A = $142

24.6667A = 74

A = 3  [The price of an adult pool admission is $3]

Use this value in either equation to find the price of a child's admission:

24C + 26A = $102

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Check to see if these prices satisfy both equations:

Monday:   16C + 42A = $142

Tuesday:  24C + 26A = $102

---

Monday:   16*(1) + 42*(3)  = $142   ?   YES

Tuesday:  24*(1) + 26*(3) = $102   ?    YES

<u>Child is $1 and Adult is $3, per person.</u>

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Answer:

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Answer:

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