what are the x-intercepts of the graph of the function f(x) = x2 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16),
joja [24]
F(x) = x^2 + 4x - 12
x-intercepts are the values of x when y = 0
x^2 + 4x - 12 = 0
(x - 2)(x + 6) = 0
x - 2 = 0 or x + 6 = 0
x = 2 or x = -6
Therefore the x-intercepts are (-6, 0), (2, 0)
Answer:
Step-by-step explanation:
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The distributive property: a(b + c) = ab + ac
12(6k + 3) + 4(7 - 5k) = 12(6k) + 12(3) + 4(7) + 4(-5k)
= 72k + 36 + 28 - 20k = 52k + 64
Answer:
Ba0.12 if b have x plus 5.10 need to be A
you can find a_6:
