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Write the equation of a line that passes the point (-6,9)and is perpendicular to a line that passes through the points (-2,1) an

Vanyuwa [196]

Answer:

hope you like my answer its-11

4 0

2 years ago

Put the following equation of a line into slope-intercept form, simplifying all fractions.

Komok [63]

Answer:

y = 2 x + 9

Step-by-step explanation:

(*￣3￣)╭

7 0

3 years ago

Read 2 more answers

Dora and boots are decorating cupcakes for a bake sale. Dora already has 25 cupcakes decorated and can decorate 10 cupcakes per

grandymaker [24]

Answer: after 5 hours, 75 cupcakes

Step-by-step explanation:

4 0

3 years ago

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$

The mean of a sample is $\bar{x}=14.371$ .

Create the below table.

Find the sum of numbers in the last column to get.

$\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982$

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889$

7 0

3 years ago

If 65 percent of the population of a large community is in favor of a proposed rise in school taxes, approximate the probability

xz_007 [3.2K]

Answer: a) 0.99917 b) 0.7054 c) 0.9820

Step-by-step explanation:

Let X denotes the number of people are in favor of a proposed rise in school taxes.

Era re given that p(probability that a person is in favor of a proposed rise )= 0.65

Sample size : n= 100

Mean= np = 100(0.65)=65

Standard deviation: $\sigma=\sqrt{np(1-p)}\\\\=\sqrt{100(0.65)(0.35)}\\\\=4.76969600708\approx4.77$

a) Now, the probability that a random sample of 100 people will contain at least 50 who are in favor of the proposition :

$P(x\geq50)=P(\dfrac{x-\mu}{\sigma}\geq\dfrac{50-65}{4.77})\\\\=P(z\geq-3.144)\\\\=P(z-z)=P(Z$

b) between 60 and 70 inclusive who are in favor;

$P(60$

c) fewer than 75 in favor.

$P(x$

3 0

3 years ago