Standard quadratic equation .. y = a x^2 + b x + c
<span>parabola 'a' not equal to zero </span>
<span>a<0 parabola opens downward </span>
<span>a>0 parabola opens upward </span>
<span>when |a| >>0 the parabola is narrower </span>
<span>when |a| is close to zero , the parabola is flatter </span>
<span>when the constant is varied it only effects the vertical position of the parabola , the shape remains the same</span>
11/21 would be the answer
Answer:
16 feet
Step-by-step explanation:
Set up a proportion where x is the height of the tree:
= 
Cross multiply and solve for x:
5x = 80
x = 16
So, the tree is 16 feet tall
Answer:
12
Step-by-step explanation:
Using the pythagorean theorem, we know that a^2+ b^2=c^2
In our case, we know b, which is 5 and c which is 13.
If we plug that into the equation, we get a^2+ 5^2 = 13^2
Next, we simplify the equation. a^2 + 25 = 169
Then we subtract 25 from 169. 169 - 25 = 144.
Lastly, we do the square root of 144 and we get 12 which is the missing side.