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Shtirlitz [24]
3 years ago
5

Can someone help me with this?​

Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

Answer:

No

Step-by-step explanation:

6^2+4^2=52

7^2=49

49 is not equal to 52, so no it is not a right triangle

jeka943 years ago
5 0

Answer:

Step-by-step explanation:

yes yes i can i just need you pitcher the one u put dose not work

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Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)​
lys-0071 [83]

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

6 0
2 years ago
Please help out asap thanks
Jet001 [13]

Answer:

there all below

Step-by-step explanation:

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2 years ago
Mplete the solution of the equation. Find the
Alex777 [14]

Answer:

-2

Step-by-step explanation:

If x=0

-3(0)+2y=-4

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We can say

2y-0=-4

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y=-2

5 0
1 year ago
What is 6/2(1+2)=?
Rufina [12.5K]

Answer:

Answer is 9

Step-by-step explanation:

Remember PEMDAS???

"parenthesis, exponents, multiplication, division, addition, subtraction"

you would first solve the addition inside of the parentheses (1 + 2 = 3), and from there finish the equation as it's written from left to right.

8 0
2 years ago
Read 2 more answers
Whats the answer to 2y^0-(3y)^0
mrs_skeptik [129]

Answer:

1

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y)^0

= 2(1) - (1)

= <u>1</u>

<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

6 0
3 years ago
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