Ask question

Ask question

All categories

3 years ago

13

Is it possible to construct a triangle with side lengths of 11 cm, 15 cm, and 21 cm? Why or why not?

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

There is only one requirement for three sides in order to be considered possible in constructing a triangle. That requirement is
<em>The sum of any of the two sides must be greater than the third side</em>

11 + 15 = 26 > 21
11+ 21 = 33 > 15
15 + 21 = 16 > 11

Since all of the combination fulfill the requirement, yes we could create the triangle with those sides.

inna [77]3 years ago

6 0

<span>

</span>
<span>Since all of the sums are greater than the third side, it is possible to make a triangle with these three sides.</span>

You might be interested in

Whats the greateats hundreds you can multiply by 6 to get close to but not go over 3236

Flura [38]

Answer:

100

Step-by-step explanation:

6×100=600

600 might not be that much close to 3236 but it's not over 3236

7 0

3 years ago

1652÷24 is this right or wrong?

Mandarinka [93]

Answer: Yup. This is right. 68 with a remainder of 20.

Step-by-step explanation:

Nice long division and nice hand writing :)

7 0

3 years ago

Read 2 more answers

Cassandra assigns values to some of the measures of triangle ABC. If angle A measures 30°, a = 6, and b = 18, which is true?

Anna [14]

Answer:

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

Step-by-step explanation:

we know that

step 1

Find the measure of angle B

Applying the law of sines

$\frac{sin(A)}{a}=\frac{sin(B)}{b}$

we have

$A=30\°$

$sin(30\°)=1/2$

$a=6\ units$

$b=18\ units$

substitute

$\frac{(1/2)}{6}=\frac{sin(B)}{18}$

$\frac{1}{12}=\frac{sin(B)}{18}$

$sin(B)=\frac{18}{12}$

$sin(B)=\frac{3}{2}=1.5$

Remember that the value of sine can not be greater than 1

therefore

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

8 0

3 years ago

7. Jena has a triangular garden with a perimeter that can be represented by 25r ^ 2 - 9r + 14 . The sum of two sides of the gard

galben [10]

Answer: $15r^2-21r+5$

Step-by-step explanation:

Given: Perimeter of triangular garden = $25r^2 - 9r + 14$

The sum of two sides of the garden = $10r^2 + 12r + 9$

Perimeter is the sum of all sides of a triangle.

Third side = Perimeter of triangular garden - sum of two sides of the garden

$=25r ^ 2 - 9r + 14-(10r ^ 2 + 12r + 9)\\\\=25r ^ 2 - 9r + 14-10r ^ 2 - 12r - 9\\\\=15r^2-21r+5$

The expression represent the third side = $15r^2-21r+5$ .

5 0

3 years ago

5. Which of the following is a multiple of 8?<br> A 4<br> C 20<br> B 8<br> D 100

snow_lady [41]

Answer:

8

Step-by-step explanation:

8 can be divisible by 8. Therefore, it would be a multiple of 8.

The first multiple of a number is always that number.

All other options given are not multiples of 8.

Hope this helps.

5 0

4 years ago

Read 2 more answers