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Zielflug [23.3K]
2 years ago
12

Lexi answers 45 questions correctly on a test and earns a 90%. How many questions were on the test?

Mathematics
1 answer:
Wewaii [24]2 years ago
5 0

Answer:50%*^^\*\*\£\€\>\€\\^^\€\\>€\€]*]*\€\!\€\^\*\*\£\££

Step-by-step explanation:

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A patient A receives 3 times the amount of certain medicine as patient B the 2 doses add to 200 milligrams. What amount does eac
torisob [31]

Patient A=150

Patient B=50


hope it helped :)

4 0
2 years ago
3 divided by what equals 94
Aleksandr-060686 [28]
282 because if u multipy 94 into 3 u get 282 and to check 282 divided by 3 is 94
8 0
3 years ago
Read 2 more answers
What is pi and why is it important
Allushta [10]
Pi<span> (π) is the ratio of the circumference of a circle to its diameter. It doesn't matter how big or small the circle is - the ratio stays the same. Properties like this that stay the same when you change other attributes are called constants.

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5 0
3 years ago
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
Can someone help solve?
icang [17]

Answer:

scaning beep no data is acquired

4 0
2 years ago
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