I hope this helps you
x^5.y^2.z/x^2.y
x^5-2.y^2-1.z
x^3.y.z
1. 864 mm^3
2.1640 cm^3
3. 4.0 cm
4. 150pi ft^3
Answer: Our required probability is 
Step-by-step explanation:
Since we have given that
Number of coins = 3
Number of coin has 2 heads = 1
Number of fair coins = 2
Probability of getting one of the coin among 3 = 
So, Probability of getting head from fair coin = 
Probability of getting head from baised coin = 1
Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

Hence, our required probability is 
No, the answer is not 
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