The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
b
Step-by-step explanation:
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You first need to make the denominators on both fractions the same and how to do that is simple. What does 6 and 8 go into to? Well, the answer is 24. You multiply 5/6 into 4 and you should get 20/24. Then, you multiply 3/8 into 3 and you should get 9/24. Now the last part is easy, you just subtract 20/24 and 9/24 and you should get 11/24 as your answer. It cannot be simplified. Hope it helped.
Answer:
y= 3x
Step-by-step explanation:
This is honestly your basic times tables if we are being honest. We know that she read 3 paragraphs per minute. We also know that in 4 minutes, she read 12 paragraphs. 4 times 3 = 12. So the answer is y=3x.
Angle M = angle L
line MC = line LP
line DN = line AE
angle A = angle D
line FL = line HM
angle C = angle P
line TE = line ON
angle O = angle T
