Coordinates : A(1,2) B(-5,6) C(7,-4) D(-2,t) - All are taken in order

gradient of AB = (6-2)/(-5-1) = 4/-6 = -⅔
since it is quadrilateral, AB//CD
gradient of CD = -⅔
equation of CD : y-(-4)=-⅔(x-7)
y+4=-⅔x+14/3
y=-⅔x+⅔
now, sub x=-2 from D(-2,t)
since t is the y-coordinate of point D
t=-⅔(-2)+⅔
t=2

Therefore, t=2

3 0

2 years ago

Find the average rate of change of a function that contains the points (-2,3) and (2,5).

slavikrds [6]

000000000000000000000000

5 0

3 years ago

Of 10<br> Find the gradient of the line segment between the points (2,-2) and (0,-6).

Veseljchak [2.6K]

Answer:

<h3>The answer is 2</h3>

Step-by-step explanation:

The gradient of a line given two points can be found by using the formula

$m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\$

From the question we have

$m = \frac{ - 6 - - 2}{0 - 2} = \frac{ - 6 + 2}{ - 2} = \frac{ - 4}{ - 2} = 2 \\$

We have the final answer as

Hope this helps you

6 0

3 years ago