Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base = ![\sqrt[3]{3}\times s^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%20s%5E%7B2%7D)
= ![\sqrt[3]{3}\times 2^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%202%5E%7B2%7D)
On solving we get:
Area of the base(b) = 
Then, we find the perimeter(p) :
Perimeter = s × 6

Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.




As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².
Answer:
Step-by-step explanation:
volume of soil = 12×8×(12-2) = 960 in³
Answer:
x = 1/3
Step-by-step explanation:
Answer:
x = 27.2
Step-by-step explanation:
Apply trigonometric function to solve for x.
Reference angle = 54°
Side length opposite to reference angle = 22
Hypotenuse = x
We would apply SOH:
Sin 54 = Opp/Hyp
Sin 54 = 22/x
x*sin 54 = 22
x = 22/sin 54
x = 27.1934955 ≈ 27.2 (nearest tenth)