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Zolol [24]
4 years ago
9

Can someone explain to me multi step algebra equations? 15 points Thaaaanks~

Mathematics
1 answer:
aalyn [17]4 years ago
7 0
So take 4x-2x=4                                                                                                        first combine like terms so now u have 2x=4.          now you will isolate the x to find what it equals. divide 2 from both sides so u have x=2.                                      did this help any?  

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the length of a new rectangular playing field is 3 yards longer than quadruple the width. if the perimeter of the rectangular pl
zalisa [80]

Answer:

length = 235 yd

width = 58 yd

Step-by-step explanation:

Let the width be W.

L = 4W + 3

perimeter = 2(L + W)

perimeter = 2(4W + 3 + W)

perimeter = 2(5W + 3) = 10W + 6

We are told the perimeter = 586 yd

10W + 6 = 586

10W = 580

W = 58

L = 4W + 3 = 4(58) + 3 = 232 + 3 = 235

length = 235 yd

width = 58 yd

8 0
2 years ago
Find the value of x.
Sergio [31]

540 - [(180 - 86) + (180 - 76) + (180 - 41) + 9180 - 98) ]

= 540 - (94 + 104 + 139 + 82)

= 540 - 419

= 121

x = 180 - 212

x = 59

4 0
4 years ago
If f(x) = 3x2 - 2x + 5, find f(-2)<br> A) -27 <br> B) -11 <br> C) -3 <br> D) 21
Digiron [165]

Answer:

D

Step-by-step explanation:

You have to be careful that you treat 21 as special. It is the only positive number. As you do the problem, keep an eye on 21.

f(-2) = 3x^2 - 2x + 5                Put -2 wherever you see an x

f(-2) = 3(-2)^2 - 2(-2) + 5         Calculate the first term.    

f(-2) = 3(4) - 2(-2) + 5              Remove the brackets of the second term

f(-2) = 12 + 4 + 5                     Combine

f(-2) = 21

7 0
3 years ago
Read 2 more answers
A rectangular garden measuring 13 meters by 15 meters is to have a gravel pathway of constant width built all around it. There i
Shtirlitz [24]

Let w represent width of the pathway.

We have been given that a rectangular garden measuring 13 meters by 15 meters is to have a gravel pathway of constant width built all around it.

Since pathway will be on all sides, so new length and width of garden with pathway would be 13+2w by 15+2w.

We are also told that there is enough gravel to cover 80 square meters. This means that area f pathway should be equal to 80 square meters.

The area of the pathway will be equal to area of garden with new dimensions minus area of garden with original dimensions.

We know that area of rectangle is width times length.

\text{Area of pathway}=(15+2w)(13+2w)-15(13)

Since we are asked to write an inequality that represents all possible widths(w), in meters, of the pathway, so area of pathway should be less than or equal to 80 square meters.

(15+2w)(13+2w)-15(13)\leq 80

Therefore, our required inequality would be (15+2w)(13+2w)-15(13)\leq 80.

8 0
3 years ago
What is the slope of the line that passes through the points -(9, -5) and (-1, -9)?
Otrada [13]

Answer:

-1.75

Step-by-step explanation:

-9 - 5 / -1 - (-9)
-14/8
-1.75

7 0
3 years ago
Read 2 more answers
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