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Aleksandr [31]
3 years ago
9

The Map of a biking trail is drawn on a coordinate grid

Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0
It is 19. Hope this helps!!
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Simplify the expression: <br><br> [15 +3(2) - 0]0<br><br> A) 4<br> B) -1<br> C) 0<br> D) 3
raketka [301]

Answer:

The answer is C. So yeah.

3 0
3 years ago
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What is the explicit formula for this arithmetic sequence?<br>3,9,15,21,27​
denis-greek [22]

Answer:

Step-by-step explanation:

Formula is to add 6. As you can see: 3+6=9; 9+6=15; 15+6=21 and 21+6=27.

I hope this was helpful.

8 0
3 years ago
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here a subtraction problem that has been solved incorrectly what is the right answer for 74-25=59 but do it in the addition sent
madam [21]

Answer:

the equation is wrong

Step-by-step explanation:

=> 74-25=59

since 74 - 25 equals to 59 in order to find the addition sentence that will check the subtraction problem is true and 59 and 3/5 or you can add add 59 and 25 to check if the problem was solved correctly

=> 59+25

add 59 to 25

=> 84

this means the question is wrong

5 0
2 years ago
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Find m2C.<br> D<br> 18<br> С<br> 9<br> B<br> o<br> mZC=
jeka94
Give me the points thanks
3 0
3 years ago
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Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
3 years ago
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