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mixas84 [53]
3 years ago
11

Solve equation 2 cot² x + 2 = 7 + 3 cot x for

TexFormula1" title="0 \leqslant x \leqslant 360" alt="0 \leqslant x \leqslant 360" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
masya89 [10]3 years ago
6 0

Answer:

Look below.

Step-by-step explanation:

2 (cotx)^{2}   + 2 = 7 + 3 cot x\\let \\ u=cotx\\2u^2+2=7+3u\\2u^2-3u-5=0\\x=\frac{-(-3)+\sqrt{9-4(2)(-5))} }{2(2)} \\x=\frac{-(-3)-\sqrt{9-4(2)(-5))} }{2(2)} \\x={11/4}\\x=-1\\\\u=cotx\\x=arccotu\\x_{1}=arccot(-1) \\x_{2}=arccot(11/4)\\

Calculate x1 and x2 in calculator. Check for domain.

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The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct
Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

5 0
3 years ago
Read 2 more answers
Use the parabola tool to graph the quadratic function f(x)=−5x^2−2.
LiRa [457]
Desmos.com and plug in the equation
3 0
3 years ago
PLEASEHELP!
denis-greek [22]
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0
4 years ago
Area of sector................................
sveticcg [70]

Answer:

A ≈ 25.1 cm²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{\frac{4\pi }{9} }{2\pi }

  = π × 6² × \frac{\frac{4\pi }{9} }{2\pi }

  = 36π × \frac{\frac{4\pi }{9} }{2\pi }

  = 18 × \frac{4\pi }{9}

  = 2 × 4π

  = 8π

  ≈ 25.1 cm² ( to the nearest tenth )

3 0
2 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
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