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3 years ago

If the equation y² - (K-2y + 2k +1 = 0with equal roots find the value of k

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

y² - (K- 2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

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Answer:

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If the equation y² - (K-2y + 2k +1 = 0with equal roots find the value of k​

If the equation y² - (K-2y + 2k +1 = 0with equal roots find the value of k