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Damm [24]
2 years ago
15

Area of sector................................

Mathematics
1 answer:
sveticcg [70]2 years ago
3 0

Answer:

A ≈ 25.1 cm²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{\frac{4\pi }{9} }{2\pi }

  = π × 6² × \frac{\frac{4\pi }{9} }{2\pi }

  = 36π × \frac{\frac{4\pi }{9} }{2\pi }

  = 18 × \frac{4\pi }{9}

  = 2 × 4π

  = 8π

  ≈ 25.1 cm² ( to the nearest tenth )

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8090 [49]

Answer:

3m == 5w, that means for such unit, there is a 2 person difference

30 person difference = 30/2 = 15units

and again one unit means 3m and 5w

so 15*3men, and 15*5women

and you can check the difference is 30

8 0
3 years ago
Which is the best estimate 9.6-6.2
velikii [3]
The best estimate is probably 4
6 0
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Name the postulate or theorem you can use to prove the triangles congruent
Lesechka [4]

Answer:

ASA

Step-by-step explanation:

if you understood the other, similar questions now, this one is really, really easy.

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6 0
3 years ago
A function is shown: f(x) = 36x² - 1.
givi [52]

Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)

<h3>What are equivalent functions?</h3>

Equivalent functions are different functions that have equal values when evaluated and compared

<h3>How to determin the equivalent function that best shows the x-intercepts on the graph?</h3>

The function is given as:

f(x) = 36x^2 - 1

Express 1 as 1^2

f(x) = 36x^2 - 1^2

Express 36x^2 as (6x)^2

f(x) = (6x)^2 - 1^2

Apply the difference of two squares.

This is represented as:

(a + b)(a - b) = a^2 - b^2

So, we have the following equation

f(x) = (6x - 1)(6x + 1)

Based on the given function, the equivalent function that best shows the x-intercepts on the graph is f(x) = (6x - 1)(6x + 1)

Read more about equivalent function at:

brainly.com/question/2972832

#SPJ1

8 0
2 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
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