Answer:
The percentage of admitted applicants who had a Math SAT of 700 or more is 48.48%.
Step-by-step explanation:
The Bayes' theorem is used to determine the conditional probability of an event <em>E</em>, belonging to the sample space S = (E₁, E₂, E₃,...Eₙ) given that another event <em>A</em> has already occurred by the formula:
Denote the events as follows:
<em>X</em> = an student with a Math SAT of 700 or more applied for the college
<em>Y</em> = an applicant with a Math SAT of 700 or more was admitted
<em>Z</em> = an applicant with a Math SAT of less than 700 was admitted
The information provided is:
Compute the value of as follows:
Compute the value of P (Y|X) as follows:
Thus, the percentage of admitted applicants who had a Math SAT of 700 or more is 48.48%.
Answer:
It is one of these two options
Step-by-step explanation:
They suspect something strange may be going on.
They know what caused the flash of light but do not want to say it.
Answer:
Draw a double bar graph for the given information.
Class 5th 6th 7th 8th 9th
No. of Boys 20 40 25 35 20
No. of Girls 30 35 20 25 40
I hope it is helpful...
Answer:
(- 2, - 4 ) and (3, 10 )
Step-by-step explanation:
(2)
Given the 2 equations
4x - 7y = 20 → (1)
x - 3y = 10 → (2)
Rearrange (2) expressing x in terms of y, that is
x = 10 + 3y → (3)
Substitute x = 10 + 3y into (1)
4(10 + 3y) - 7y = 20 ← distribute and simplify left side
40 + 12y - 7y = 20
40 + 5y = 20 ( subtract 40 from both sides )
5y = - 20 ( divide both sides by 5 )
y = - 4
Substitute y = - 4 into (3) for corresponding value of x
x = 10 + 3(- 4) = 10 - 12 = - 2
Solution is (- 2, - 4 )
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(3)
3x + y = 19 → (1)
4x - y = 2 → (2)
Adding the 2 equations term by term will eliminate the y- term
(4x + 3x) + (- y + y) = 19 + 2, that is
7x = 21 ( divide both sides by 7 )
x = 3
Substitute x = 3 into either of the 2 equations and solve for y
Substituting into (1)
3(3) + y = 19
9 + y = 19 ( subtract 9 from both sides )
y = 10
Solution is (3, 10 )