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slava [35]
3 years ago
8

5c + 16.5 = 13.5 + 10c c =

Mathematics
1 answer:
olga55 [171]3 years ago
4 0

Answer:

3/5 or 0.6

Step-by-step explanation:

− 5 c + 16.5 = 13.5

− 5 c = − 3

c=3/5

c=0.6

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Find the distance between points M(-7,5) and Z(2,-3)
julsineya [31]

Hey there! I'm happy to help!

To find the distance between two points, you find the difference between the x values, square that, find the difference between the y values, square that, add the two numbers you got, and then find the square root.

We find the difference between the x values.

-7-2=-9

Square it.

-9²=81

We find the difference between the y-values.

5--3

5+3=8

We square it.

8²=64

We add the numbers we got.

81+64=145

We square root.

√145≈12.04

This formula comes from the Pythagorean Theorem! Now you can find the distance between any two points! Have a wonderful day! :D

8 0
3 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
It takes a person 50 minutes to get to campus. He spends t minutes walking to the bus stop and the rest of the time riding the b
amid [387]

Answer:

16.2

Step-by-step explanation:

cause. ur a noob at math

8 0
2 years ago
What equation do you obtain when you solve the formula A = 1/2bh for h?ASAP PLEASE
Katen [24]

Answer:

2Ab=h

Step-by-step explanation:

A=1/2bh

2A=bh

2Ab=h

8 0
3 years ago
What is the slope line that passes through(17,-13) and (17,8)?
r-ruslan [8.4K]
Undefined

Slope is equal to the change in
y
y
over the change in
x
x
, or rise over run.

The change in
x
x
is equal to the difference in x-coordinates (also called run), and the change in
y
y
is equal to the difference in y-coordinates (also called rise).

Substitute in the values of
x
x
and
y
y
into the equation to find the slope.

The expression contains a division by
0
0
The expression is undefined.
3 0
2 years ago
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