Hello
Explanation:
well I don't know if I can answer you well but I try .... I think it's HC2H202Cl... Thank you for your attention ✌️
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Answer : The correct option is, (A) 51.1%
Explanation :
Mass percent : It is defined as the mass of the given component present in the total mass of the compound.
Formula used :
First we have to calculate the mass of 
and 
.
Mass of = 18 g/mole
Mass of 
= 7 × 18 g/mole = 126 g/mole
Mass of = 246.47 g/mole
Now put all the given values in the above formula, we get the mass percent of in .
Therefore, the mass percent of in is, 51.1%
Answer:
Explanation:
Initial burette reading = 1.81 mL
final burette reading = 39.7 mL
volume of NaOH used = 39.7 - 1.81 = 37.89 mL .
37.89 mL of .1029 M NaOH is used to neutralise triprotic acid
No of moles contained by 37.89 mL of .1029 M NaOH
= .03789 x .1029 moles
= 3.89 x 10⁻³ moles
Since acid is triprotic , its equivalent weight = molecular weight / 3
No of moles of triprotic acid = 3.89 x 10⁻³ / 3
= 1.30 x 10⁻³ moles .
