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Kazeer [188]
3 years ago
11

How to make vape oil from scratch for a vape pen

Chemistry
2 answers:
Julli [10]3 years ago
3 0
If you’ve been vaping for a while now, you may be craving some new vape juice flavors to try with your favorite RDA, RTA, or Box Mod.

You might find that ordering large batches of your all day vape juice flavors can prove a bit on the expensive side, particularly if your tastes run toward the premium e juice priced at over $20 per bottle.

Surely there must be a better way than taking out payday loans to get your hands on that Peanut Butter Crunch-flavored creation you just have to have in your sub-ohm tank?

Fortunately, when you know how to make homemade vape juice it can be a fun and fascinating hobby that has the delightful side effect of saving you loads of cash using cheap vape juice.

Many people hear “diy vape juice” and get visions of a mad scientist in a dank lab constantly flirting with explosion by mixing volatile chemicals while laughing insanely.

The reality is that it’s relatively easy to learn how to make your own vape juice at home, and we’re going to attempt to cover all the facets involved.

Are you interested in making your own e juice?
Murrr4er [49]3 years ago
3 0
You need some VG... You can buy it in big bottles, mix in some flavoring which is very easy to get and add some concentrated nicotine if you need to as well

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i think that the answer is d. millions of small rocky objects

5 0
3 years ago
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A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

Divide each element by its atomic mass

N: 30.45 / 14.00 = 2.175 mol

O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

Divide both by the smaller number

N: 2.175 / 2.175 = 1

O: 4.346875 / 2.175 = 1.999 = 2

5) Empirical formula: NO2

6) mass of the empirical formula

14.00 + 2 * 16.00 = 46.00 g

7) Find the number of moles of the gas using the equation pV = nRT

=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)

=> n = 0.01769 moles

8) Find molar mass

molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol

9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
3 0
3 years ago
The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
Inessa05 [86]

Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.

Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

                          PbBr₂ ----------> Pb⁺² + Br⁻

                                                     S      2S

Ksp = [Pb⁺²] [ Br⁻]

Ksp = (S) (2S)²

Ksp = 4S³

6.60 × 10⁻⁶ = 4S³

S = 0.0118M

Hence, the Molar solubility S is 0.0118M.

Learn more about Molar solubility here, brainly.com/question/16243859

#SPJ4

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The outside boundary of an animal cell
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Plasma membrane is the answer
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What is the compound name to C5H6?
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When your brain goes numb, you can call that mental freeze

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