2.(03.01 LC)

Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest at the end of the year

MAVERICK [17]

Answer: he invested $5300 at 11% and $1000 at 6%

Step-by-step explanation:

Let x represent the amount which he invested in the first account paying 11% interest.

Let y represent the amount which he invested in the second account paying 6% interest.

He Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest. This means that

x + y = 6300

The formula for determining simple interest is expressed as

I = PRT/100

Considering the first account paying 11% interest,

P = $x

T = 1 year

R = 11℅

I = (x × 11 × 1)/100 = 0.11x

Considering the second account paying 6% interest,

P = $y

T = 1 year

R = 6℅

I = (y × 6 × 1)/100 = 0.06y

At the end of the year, he had earned $643 in interest , it means that

0.11x + 0.06y = 643 - - - - - - - - - -1

Substituting x = 6300 - y into equation 1, it becomes

0.11(6300 - y) + 0.06y = 643

693 - 0.11y + 0.06y = 643

- 0.11y + 0.06y = 643 - 693

- 0.05y = - 50

y = - 50/ - 0.05

y = 1000

x = 6300 - y = 6300 - 1000

x = 5300

7 0

3 years ago

Ann is mailing packages. Each small package costs her $2.10 to send. Each large package costs her $3.30. How much will it cost h

Liula [17]

Answer:

$35.76

Step-by-step explanation:

12.60

23.10

--------

35.76

4 0

2 years ago

Read 2 more answers

Raju bought seven notebooks of two hundred pages and five of hundred pages, for 107 rupees. Joseph bought five notebooks of two

olga nikolaevna [1]

Answer:

Large books = 11

Small books = 6

Step-by-step explanation:

7x + 5y = 107

7x = 107 - 5y

x = 107/7 - 5y/7

5x + 7y = 97

5 (107/7 - 5y/7) + 7y = 97

535/7 - 25y/7 + 7y = 97

535/7 + 24y/7 = 97

535 + 24y = 679

24y = 679 - 535

y = 144/24 = 6: So x =

7x + 5(6) = 107

7x = 107-30

x = 77-7 = 11

8 0

3 years ago

After college you start a job earning $40,000 a year. You get a 6% raise each year.

alex41 [277]

Answers: A) $44,944
B) $50,499.0784

Math: Using the percentage calculator linked below 6% of $40,000 is $2,400. Since you're getting your second raise after your first and since it is a 6% raise from what you're getting paid at that time we add pay raise 1 to your starting pay before calculating the 6% for pay raise 2. $40,000+$2,400=$42,400. 6% of $42,400 is $2,544. $42,400+$2,544=$44,944, Since that is two pay raises that would be your earnings at the end of year two (answer A).
We continue calculating 6% then adding that onto the total before calculating it for the next year for problem B.
6% of $44,944 is $2,696.64. $44,944+$2,696.64=$47,640.64.
6% of $47,640.64 is $2,858.4384. $47,640.64+$2,858.4384=$50,499.0784. That's answer B.

Hopefully you can figure out C on your own! I feel a little bad for giving a partial answer but I think you can do this!

Percentage calculator used-https://percentagecalculator.net/
Note: can't handle commas, remove all commas before entering data in.

7 0

3 years ago

Consider the line y = 7x-9.

KatRina [158]

$y = \frac{-1}{7}x -\frac{8}{7}$ is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

Solution:

Given that line is:

y = 7x - 9

The equation of line in slope intercept form is given as:

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

$7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}$

Now find the equation of line:

$\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}$

$-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}$

$\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}$

Thus the equation of line perpendicular to given line is found

<h3>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</h3>

Slopes of parallel lines are equal

Therefore, m = 7

Substitute m = 7 and (x, y) = (6, -2) in eqn 1

-2 = 7(6) + b

-2 = 42 + b

b = -44

Substitute m = 7 and b = -44 in eqn 1

y = 7x - 44

Thus equation of line parallel to given line is found

8 0

3 years ago