All categories

3 years ago

2.(03.01 LC)

Mathematics

1 answer:

strojnjashka [21]3 years ago

4 0

Answer:
7(3 + 7)
Why:
7x3=21
7x7=49

You might be interested in

Is the product of two imaginary numbers always imaginary?

Diano4ka-milaya [45]

No. i*i = -1

2i*3i=-6

now if they meant complex numbers the answer is still no

(2+4i)(2-4i) = 4-8i+8i-16 = -12

3 0

3 years ago

A group of cat owners was asked about the number of cats each owns. The results are shown in the frequency table. Number of Freq

Yakvenalex [24]

Answer:

Cats Owned B. 2 3

Hope I helped! :)

8 0

3 years ago

The weights of ice cream cartons are normally distributed with a mean weight of 8 ounces and a standard deviation of 0.4 ounce.

Alla [95]

Answer:

a) 0.373 probability that a randomly selected carton has a weight greater than 8.13 ounces

b) 0.097 probability that mean weight of 16 randomly selected carton is greater than 8.13 ounces

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 ounces

Standard Deviation, σ = 0.4 ounce

We are given that the distribution of weights of ice cream cartons is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(weight greater than 8.13 ounces)

P(x > 8.13)

$P( x > 8.13) = P( z > \displaystyle\frac{8.13 - 8}{0.4}) = P(z > 0.325)$

$= 1 - P(z \leq 0.325)$

Calculation the value from standard normal z table, we have,

$P(x > 610) = 1 - 0.627 = 0.373 = 37.3\%$

b) P(weight of 16 randomly selected cartons is greater than 8.13 ounces)

P(x > 8.13)

$P( x > 8.13) = P( z > \displaystyle\frac{8.13 - 8}{\frac{0.4}{\sqrt{16}}}) = P(z > 1.3)$

$= 1 - P(z \leq 1.3)$

Calculation the value from standard normal z table, we have,

$P(x > 8.13) = 1 - 0.903 = 0.097 = 9.7\%$

5 0

3 years ago

Given. Round

mel-nik [20]

Answer:

$\frac{15625}{4096}$

3 0

3 years ago

Please help! (Photo attached)

maks197457 [2]

The answer is 56.52 units

4 0

3 years ago