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Oksana_A [137]
3 years ago
11

Please help thanks I need it in an hour please

Mathematics
2 answers:
Savatey [412]3 years ago
7 0
Use gauth math or photo math both free and always works and shows all the work
sp2606 [1]3 years ago
3 0

Answer:

i cant see the picture sorry

Step-by-step explanation:

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Write an equation of the line that is perpendicular to the line y = 2x + 8, and which goes through the point (2,12)
harina [27]

Answer:

y=-1/2 x +13

Step-by-step explanation:

negative reciprocal of 2 is -.5 and then find what y intercept it would be to go through that point

3 0
3 years ago
How to write a polynomial function with rational coefficients in standard form with the given zeros?
Gennadij [26K]
If you have as many zeros (z1, z2,... zn) as the degree of the polynomial function (n), then the function equation is given by:

f(x) = k (x - z1) (x - z2) ··· (x - zn)

where k is a constant. To determine this constant you need additional information (e.g. another point of the function).

You might also have less zeros than the degree of the polynomial, because some of them have a multiplicity greater than 1. Let z1,...,zr be the zeros, and m1,...mr be the multiplicity of each zero, where m1+m2+...+mr=n (we assume the sum of all multiplicities equals the degree of the polynomial). In this case, you can use:

f(x)=k(x-z_1)^{m_1} (x-z_2)^{m_2} \cdots (x-z_r)^{m_r}

Again, you have an undetermined constant factor.

From any of the two expressions above, you have to apply the distributive property to go on to the standard form.

An example: the zeros of a 3-degree polynomial function are -2, 1 and 3. The function equation is of this form:

f(x)=k(x+2)(x-1)(x-3) = k(x^3-2x^2-5x+6)

If you don't have all the zeros, or the sum of multiplicities does not equal the degree of  the polynomial, you have not enough information to write the equation of the function.

4 0
3 years ago
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One a
Minchanka [31]

Answer:

II. One and only one solution

Step-by-step explanation:

Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

Let assume the equation is given as;

x + 3y = 11 .... 1

x - y = -1 ....2

Using elimination method

Subtract equation 1 from 2

(x-x) + 3y-y = 11-(-1)

0+2y = 11+1

2y = 12

y = 12/2

y = 6

Substitute y = 6 into equation 2:

x-y = -1

x - 6 = -1

x = -1 + 6

x = 5

Hence the solution (x, y) is (5, 6)

<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>

<em />

4 0
3 years ago
Anyone know this answer
dem82 [27]

Answer:

Step-by-step explanation:

1 is 60 2 i 60 and 3 is 61 ;)

3 0
4 years ago
Read 2 more answers
Which is a common denominator for the numbers: 40 and 28
Archy [21]

Answer:

(a) 40 into 1120=28....28 into 1120=40 so 1120 is the denominator of 40&28

8 0
3 years ago
Read 2 more answers
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