Answer:
your do it on your own
Step-by-step explanation:
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+129x+119
y=−16x
2
+129x+119
X^2 -5x+5x - 25
Final answer : x^2 -25
I hope i helped ;)
The average rate of change of f(x) on the interval [5, 5 + h] is 1
<h3>How to find the
average rate of change of f(x) on the interval [5, 5 + h]?</h3>
The equation of the function is given as:
f(x) = x + 11
The interval is given as: [5, 5 + h]
So, we start by calculating f(5) and f(5 + h)
This gives
f(5) = 5 + 11 = 16
f(5 + h) = 5 + h + 11 = h + 16
The average rate of change of f(x) on the interval [5, 5 + h] is then calculated as:
Rate = [f(5 + h) - f(5)]/[5 + h - 5]
Substitute the known values in the above equation
Rate = (h + 16 - 16)/(5 + h - 5)
Evaluate the sum and the difference
Rate = h/h
This gives
Rate = 1
Hence, the average rate of change of f(x) on the interval [5, 5 + h] is 1
Read more about the average rate of change at
brainly.com/question/8728504
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Answer:
#1 and # 3 maybe
Soooooooory if this wrong, This is the type of question I would get stuck on... O////O