Ask question

Ask question

All categories

andrey2020 [161]

3 years ago

8

Bella needs to paint a logo made using two right triangles. The dimensions of the logo are shown below. What is the area of the

two triangles that need to be painted?
Dimensions:
Triangle 1: 6 by 2
Triangle 2 5 by 9

1 answer:

Sergeu [11.5K]3 years ago

8 0

Answer:

It would be 28.5. First, you would find the area of the smaller triangle by using the formula a=.5bh (area=.5xbasexheight) and then when you get that, you should get 6. Then, you do the same for the larger triangle and you should get 22.5. Then, 22.5 + 6 = 28.5, giving you that answer.

Step-by-step explanation:

You might be interested in

The altitude of a triangle is increasing at a rate of 1.500 centimeters/minute while the area of the triangle is increasing at a

puteri [66]

Answer:

The base of the triangle is shrinking at a rate of $\frac{131}{32}$ centimeters per minute.

Step-by-step explanation:

The formula of the area of a triangle is given by the following expression:

$A = \frac{1}{2}\cdot b \cdot h$

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

The base of the triangle is:

$b = \frac{2\cdot A}{h}$

If $A = 98000\,cm^{2}$ and $h = 8000\,cm$ , the base of the triangle is:

$b = \frac{2\cdot (98000\,cm^{2})}{8000\,cm}$

$b = 24.5\,cm$

The rate of change of the area of the triangle in time, measured in minutes, is obtained after differentiating by rule of chain and using deriving rules:

$\frac{dA}{dt} = \frac{1}{2}\cdot h\cdot \frac{db}{dt} + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$

$\frac{dA}{dt} = \frac{1}{2} \cdot \left(h\cdot \frac{db}{dt}+b \cdot \frac{dh}{dt} \right)$

The rate of change of the base of the triangle is now cleared:

$2\cdot \frac{dA}{dt} = h\cdot \frac{db}{dt} + b\cdot \frac{dh}{dt}$

$h\cdot \frac{db}{dt} = 2\cdot \frac{dA}{dt}-b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2\cdot \frac{dA}{dt} - b \cdot \frac{dh}{dt} }{h}$

Given that $\frac{dA}{dt} = 2000\,\frac{cm^{2}}{min}$ , $b = 24.5\,cm$ , $\frac{dh}{dt} = 1500\,\frac{cm}{min}$ and $h = 8000\,cm$ , the rate of change of the base of the triangle is:

$\frac{db}{dt} = \frac{2\cdot \left(2000\,\frac{cm^{2}}{min} \right)-(24.5\,cm)\cdot \left(1500\,\frac{cm}{min} \right)}{8000\,cm}$

$\frac{db}{dt} = -\frac{131}{32}\,\frac{cm}{min}$

The base of the triangle is shrinking at a rate of $\frac{131}{32}$ centimeters per minute.

5 0

3 years ago

1. An endpoint of a line segment is (4,5) and the midpoint of the line segment is (3,−2). Find the other endpoint.

Furkat [3]

Answer:

1. (2, -9) 2. (10, 10)

Step-by-step explanation:

7 0

4 years ago

Gregory received £2400. He gave 1/3 of it to his favorite charity and spent 1/5 of it on a new violin. What fraction of his mone

Nesterboy [21]

Answer:

7/15

I hope this helps and I apologize if I'm wrong.

Can you tell me if I was wrong or right?

7 0

1 year ago

$288 8 g or $360 9 g

valentinak56 [21]

What is this asking?? 360.9g is larger.

3 0

3 years ago

Read 2 more answers

A three-digit number has tens digit two greater than the units digit and the hundreds digit one greater than the tens digit. The

Paha777 [63]

Answer:

875

Step-by-step explanation:

As given, there is a three digit number

So, let assume three digit number be `xyz`.

Now, as given tens digit is 2 greater than the unit digit.

∴ $y= 2+z$

Next, the hundred digit one greater than the tens digit.

∴ $x= 1+y$

The sum of the tens and the hundreds digits is three times the units digit.

∴ $x+y= 3z$

Now, substituting the value in the equation.

$x+y= 3z$

⇒ $(1+y)+y= 3\times (y-2)$

solving it to get value of y

⇒ $2y+1= 3y-6$

⇒ $-y= -7$

∴ $y=7$

Next, finding value of z

y= $2+z$

substituting the value of y and subtracting both side by 2

∴ z= $7-2= 5$

Last, finding the value of x

$x=1+y$

substituting the value of y

∴ x= 8

xyz= 875

5 0

3 years ago