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ycow [4]
3 years ago
15

What is the sum of -3+3x=-2(x+1)​

Mathematics
1 answer:
poizon [28]3 years ago
5 0

Answer:

The full answer in the media.Good luck!

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Answer:

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Step-by-step explanation:

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Interpreting graphs of proportional relationships

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3 years ago
Can someone help with this math question please
kherson [118]
Regarding question number 47, which is what I can read well ...
 Equation 4 (3x-2) ² = 36 It can be solved in the following way:
 -Apply distributive property
 4 (9x ²-12x +4) = 36
 -We order the terms and equalize to zero
 36x² -48x +16 -36 = 0
 36 x ² -48x -20 = 0
 The roots of this equation are
 (-48 +  √(48 ²-4 ×36 × -20)) / 2 ×36
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4 0
3 years ago
The sum of 3 consecutive odd numbers is 177. What is the value of the smallest number in the sequence
riadik2000 [5.3K]

Ok this is a very question that can solved very easily. So we know that there three numbers, and they are consecutive, this means that they are all one bigger than the number before so for example 1,2, and 3 or 20, 21, and 22. These numbers are called consecutive. Now let's just pretend that the answer to this question is the variable "x". Now x is the smallest number in all the three numbers.

Using our knowledge of consecutive numbers we can say that the next to numbers will be one more than the number before so:

(x+1) and (x+2)

So we have our three numbers: x , x+1 , and x+2. Now let's set these numbers equal to 177.

177 = x + x + 1 + x + 2 → Combine like terms.

177 = 3x + 3 → Subtract 3 from both sides.

174 = 3x → Divide both sides by 3

58 = x

So that means that our first and smallest number is going to be 58 our second number will be +1 so 59 and our third number will be +2 so 60.

So the three numbers will be 58, 59, and 60.

Hope this helped.

4 0
3 years ago
- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t
vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

=x^2-12x+37\mathrm{The\: parabola\: params\: are\colon}a=1,\: b=-12,\: c=37x_v=-\frac{b}{2a}x_v=-\frac{\left(-12\right)}{2\cdot\:1}\mathrm{Simplify}x_v=6y_v=6^2-12\cdot\: 6+37

Simplify:

y_v=1

\mathrm{Therefore\: the\: parabola\: vertex\: is}\mleft(6,\: 1\mright)\mathrm{If}\: a\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}a=1\mathrm{Minimum}\mleft(6,\: 1\mright)\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

y=x^2-12x+37\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}a=1,\: b=-12x=\frac{-\left(-12\right)}{2\cdot\:1}\mathrm{Refine}

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

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