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Naddika [18.5K]

2 years ago

9

What is a unite rate

2 answers:

mezya [45]2 years ago

8 0

Answer:

A "ratio" is any comparison of two numerical measurements. Each measurement is called a "term."

A "rate" is a ratio in which the two terms are measured in different units. …

A "unit rate" is a rate in which the second term equals "1." When calculating a unit rate, you need to determine how much of the first term exists for …

Step-by-step explanation:

r-ruslan [8.4K]2 years ago

5 0

Answer:

A quantity compared to exactly one unit of another quantity

Step-by-step explanation:

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TJ bought 3 t-shirts & a pair of shorts for $15. If each shirt was $4.25, how much were the shorts?

arsen [322]

You have $15.00 and each shirt you bought was $4.25
$4.25x3=$12.75
$15.00-$12.75= $2.25

So your shorts were $2.25

7 0

3 years ago

A rectangular equation that is not a function will not be a function in any coordinate system. True or false ?

OLga [1]

Answer:

the answer is false

3 0

3 years ago

Find all points on the x-axis that are 14 units from the point (4, -7).

BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

$\sqrt{(x-4)^2+(0-(-7))^2} = 14$

$\sqrt{x^2 - 8x + 16 + 49} = 14$

$\sqrt{x^2 - 8x + 65} = 14$

$(\sqrt{x^2 - 8x + 65})^2 = 14^2$

$x^2 - 8x + 65 - 196 = 0$

$x^2 - 8x - 131 = 0$

So $a = 1, b = -8, c = -131$

$\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588$

$x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12$

$x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12$

The points are: (16.12,0),(-8.12,0).

4 0

2 years ago

Please help me!!! Click the image to see the question I need help

VikaD [51]

Answer:

it on the paper

Step-by-step explanation:

7 0

3 years ago

Help please i need this fast

allochka39001 [22]

<less than
>greater than
≤less than or equal to
≥greater than or equal to

it flips (changes direction)

10+x≤25
x≥15

8 0

3 years ago