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aivan3 [116]
3 years ago
9

Rewrite the following polynomial in standard form. 9 + 3x – x2

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

it's already in standard form <3

Step-by-step explanation:

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A number is k units to the left of 0 on the number line describe the location of it's opposite
aivan3 [116]
The number is 0-K so its opposite would be positive. The answer would be 0+K
4 0
3 years ago
A plastic bin contains red, yellow, and green key chains. Out of 350 key chains, 10% percent are yellow. Of the remaining key ch
Ulleksa [173]
Hello there! Thank you for asking your question here at Brainly! I will be assisting you with answering this question, and will be teaching you how to handle it on your own in the future.

We have 350 total keychains, in which 10% are yellow, 3/5 are green, and x are red. We will be solving for red, but we need to subtract 10% and 3/5 from 350.

So, let's find out how much 10% of 350 is.
Since 10% is equivalent to 1/10, we can divide 350 by 10 to find how many yellow key chains there are.
350 / 10 = 35.
There are 35 yellow key chains. We can subtract this from 350 to narrow it down.
350 - 35 = 315.

Now, let's find how much 3/5 of 350 is, and subtract it from our new number (315).

Divide 350 by 5, and then multiply that quotient by 3.
350 / 5 = 70.
70 x 3 = 210.

We have 210 green key chains. Now let's subtract that from 315. This will give us the remaining key chains - which are red.
315 - 210 = 105.

There are 105 red key chains.

I hope this helps!
3 0
3 years ago
Find the rate of change between (4, 0) and (6, 1).
mestny [16]

Answer: 0.5.

Step-by-step explanation:

6 0
2 years ago
Write 3954 in expanded form using powers of 10
zavuch27 [327]
3954=3\underbrace{954}_{\leftarrow3}=\boxed{3.954\cdot10^3}
3 0
3 years ago
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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