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VLD [36.1K]
2 years ago
14

Which equation represents a line parallel to the y axis?

Mathematics
1 answer:
scoray [572]2 years ago
7 0
B: x=4 hope this helped!!
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For safety reasons, 4 different alarm systems were installed in the vault containing the safety deposit boxes at a Beverly Hills
Evgen [1.6K]

Answer:

<em>99.93%</em>

Step-by-step explanation:

<u>Probability of Independent Events</u>

Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.

We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.

We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.

The probability that none of the systems detect the theft is

P(0)=q^4=0.16^4=0.00065536

Thus, the probability that at least one of the systems detect the theft is

P(x\geq1)=1-P(0)=1-0.00065536=0.9993

That means a 99.93%

3 0
3 years ago
A shelf has 20 bags of potatoes. Two of the bags have potatoes starting to go bad. The probability of drawing a bag with bad pot
nekit [7.7K]

Probability of drawing bad potatoes = 0.1

The probability of drawing a bag with bad potatoes is less than 1.

The probability of drawing a bag with good potatoes is greater than 0

The probability of drawing a bag with bad potatoes as a decimal .

The probability is 20% which means 20 by hundred , which means there is a chance of being its ok.

probability of bad potatoes = 2/20

=1/10

=0.1

probability of good potatoes = 1- ( probability of bad potatoes)

=1-0.1

=0.9

To learn more about probability

brainly.com/question/173579

#SPJ4

3 0
1 year ago
Let f(x) = 3x ­- 6 and g(x) = x ­- 2. Find f/g and its domain
Neko [114]
F(x) = 3x-6
g(x) = x-2

so f/g = 3(x-2)/(x-2) = 3

hope this will help you 
7 0
3 years ago
Read 2 more answers
Find the difference 0.2 - 0.05 =
Ugo [173]

Answer:

0.2-0.05=0.15

Step-by-step explanation:

0.2=0.20

0.20-0.05=0.15

5 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.
sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then  

\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

\bf G(x,y) = (x, y, 3-x^2-y^2)

with 0≤ x≤1 and  0≤ y≤1

So

\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)

we also have

\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)

and so

\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and  0≤ y≤1

\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0
3 years ago
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