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3 years ago

What is 8x2/5? (Plz answer fast)

Mathematics

1 answer:

Basile [38]3 years ago

6 0

Answer:

fraction: 3 1/5

Step-by-step explanation:

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Please help me answer this <br><br> Explain you’re answer <br><br> Will give braisnlt

fgiga [73]

Answer:

b should be correct

Step-by-step explanation:

you times the amount of hours by 20 and then add the 35 into the total value of 120

5 0

3 years ago

I will gove brainlist ..The line graph shows the amount of water loss in a leaking tank during 7 hours.The owner pays $1for ever

kramer

Answer:

The owner will have to pay $ 125 after 2 hours.

Step-by-step explanation:

Given that the line graph shows the amount of water loss in a leaking tank during 7 hours, and the owner pays $ 1 for every 8 liters of water lost, to determine how much will he have to pay after 2 hours the following calculation must be performed :

((6000 - 5000) / 8) x 1 = X

(1000/8) x 1 = X

125 x 1 = X

125 = X

Therefore, the owner will have to pay $ 125 after 2 hours.

8 0

3 years ago

Which addition sentences show you how to find 16-9?

Valentin [98]

This dosent make sense and where are the sentences ;-;

5 0

4 years ago

HELP RN PLEASEEE for a quiz

sattari [20]

Answer:

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

parallel lines have the same slopes , perpendicular lines have slope which are opposite reciprocals.

~~~~~~~~~~~~~~~

A( 3 , 5 )

B( - 2 , 7 )

$m_{AB}$ = $\frac{7-5}{-2-3}$ = - $\frac{2}{5}$

C( 10 , 5 )

D( 6 , 15 )

$m_{CD}$ = $\frac{15-5}{6-10}$ = - $\frac{5}{2}$

The answer is (A) Neither

8 0

2 years ago

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

3 years ago