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pychu [463]
3 years ago
13

Solve the following system of equations and show all work. y = 2x^2 y = –3x −1

Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:(- 1/2, 1/2)

(- 1, 2)

Step-by-step explanation:

The given system of equations is expressed as

y = 2x²- - - - - - - - - - - - - - -1

y = - 3x - 1- - - - - - - - - -- - - -2

We would apply the method of substitution by substituting equation 1 into equation 2. It becomes

2x² = - 3x - 1

2x² + 3x + 1 = 0

We would find two numbers such that their sum or difference is 3x and their product is 2x². The two numbers are 2x and x. Therefore,

2x² + 2x + x + 1 = 0

2x(x + 1) + 1(x + 1) = 0

2x + 1 = 0 or x + 1 = 0

x = - 1/2 or x = - 1

Substituting x = - 1/2 into equation 1, it becomes

y = 2(-1/2)² = 1/2

Substituting x = - 1 into equation 1, it becomes

y = 2(-1)² = 2

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Step-by-step explanation:

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Solve the system of linear equations by substitution x-y=-4 2x+y=4
mylen [45]

Answer:

Given:

x-y=-4

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Step-by-step explanation:

x-y=-4

2x+y=4

add both the equation, we get

⇒  x-y=-4

  2x+y=4

⇒3x=-4+4

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3 years ago
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ASHA 777 [7]
\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
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\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
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\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
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4 0
3 years ago
If the m∠1=123° m ∠ 1 = 123 ° and m∠2= (2x+7)° m ∠ 2 = ( 2 x + 7 ) ° , determine the value of x that supports l∥m l ∥ m . Show y
Georgia [21]

Answer:

25

Step-by-step explanation:

Let us assume that m<1 nad m<2 are supplementary. Since the sum of supplementary angles is 180degrees, hence;

<1 + <2= 180

123+2x+7 = 180

130+2x = 180

2x = 180 - 130

2x = 50

x = 50/2

x = 25

Hence the value of x is 25

5 0
3 years ago
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