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solniwko [45]
3 years ago
6

Can someone help me please?

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

This is the graph of the question

Step-by-step explanation:

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How to solve this inequality -8×+18>-22
Ksju [112]

Answer:

x < 5

Step-by-step explanation:

<u>Step 1:  Solve for x</u>

-8x + 18 > -22

-8x + 18 - 18 > -22 - 18

-8x / -8 > -40 / -8

<em><u>When dividing by negative, it flips the sign</u></em>

x < 5

Answer: x < 5

4 0
3 years ago
What is the fornula for find arithemetic ewuation​
-Dominant- [34]

Answer:

a_{n} = a_{1} + (n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.

3 0
3 years ago
Radius of a semi circle
Ivahew [28]
The area for semi circle is: (pi)(r^2)/2

A= 3.142 x (8.2)^2 / 2

A= 110.8 cm^2
8 0
2 years ago
Read 2 more answers
The shape below is transformed to another shape.
netineya [11]

Answer:

Option 4 is the image of the given figure.

Step-by-step explanation:

We are given that,

The shape EFGHCD is transformed to form another shape.

From the options, we see that,

Figure 2 and 3 does not have the same vertices as that of the figure.

So, they are discarded.

Since, after transforming a figure, we get a new figure.

So, the vertices cannot have same name as that of the original figure.

So, option 1 is discarded.

Thus, we get,

Option 4 is the image of the given figure after transformation as shown below.

5 0
3 years ago
Read 2 more answers
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
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