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Volgvan
3 years ago
14

Which of the following have the correct solution? Check all

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Step-by-step explanation:

To do this, we will substitute the x values to their corresponding equations,

1)

2x + 5 \\  = 2(7) + 5 \\  = 14 + 5 \\  = 19

Given 2x + 15 = 19

Calculated 2x + 15 = 19

Given = Calculated, this solution is correct.

2)

3 + x + 2 -x \\  = 3 + 3 + 2 - 3 \\  = 8 - 3 \\  = 5

Given 3 + x + 2 - x = 16

Calculated 3 + x + 2 - x = 5

Given not equal to calculated, this solution is incorrect.

3)

\frac{x + 2}{5}  \\  =  \frac{8 + 2}{5}  \\  =  \frac{10}{5}  \\  = 2

Given (x+2)/5 = 2

Calculated (x+2)/5 = 2

Given = Calculated, this solution is correct.

4)

6 = 2x - 8 \\ 2x - 8 = 6

2x - 8  \\  = 2(7) - 8 \\  = 14 - 8 \\  = 6

Given 2x - 8 = 6

Calculated 2x - 8 = 6

Given = Calculated, this solution is correct.

5)

14 =  \frac{1}{3} x + 5 \\  \frac{1}{3} x + 5 = 14

\frac{1}{3} x + 5 \\  =  \frac{1}{3}(18) + 5 \\  =  \frac{18}{3}   + 5 \\  = 6 + 5 \\  = 11

Given 1/3x + 5 = 14

Calculated 1/3x + 5 = 11

Given not equal to Calculated, this solution is not correct.

Therefore the Correct solutions are 1,3 and 4.

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Step-by-step explanation:

The student needs to check all algebraic and mathmatical calculations for errors and typos.  I'm old and have been prone to making mistakes.

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Volume of a cylinder  =  π(radius)²h is the normal form since they provided the diameter I will use     Volume of a cylinder  =  π(diameter/2)²h

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             writing if a little more condensed

VolA  - VolB  =  π(D for A/2)²H of A  -   π(D for B/2)²H of B

    Va - Vb    =   π(Da/2)²Ha  -   π(Db/2)²Hb

                     =  π [(Da²/2²)Ha - (Db²/2²)Hb]      factored out the π

                     =  π/4 [ Da²Ha  - Db²Hb]              factored out the (1/2)²

             I can't think of any other algebraic steps

Va - Vb = Water Remaining in Container A  =  π/4 [ Da²Ha  - Db²Hb]            

            =  π/4 [ (12²)(13)  - (10²)(16)]

            =  π/4 [ (144)(13)  - (100)(16)]

            =  π/4 [ 1872 - 1600 ]

            =  π/4 [272]

            =  π [ 272/4 ]  

            =  π [ 136 / 2]

            =  π [ 68 ]

            =  π (68)

            =  213.6  ft³             rounded to the nearest tenth

I checking my answer by using  V = πr²h         r = d/2

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                         = π [(36)(13) - (25)(16)]

                         = π [ 468 - 400]

                         = 68 π

                         = 213.6 ft³         I got the same answer

       

            =  π

test

   

8 0
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