<h2>
<em><u>HEYA</u></em></h2>
<h3>THE MID TERM SPLITTING OF THE EQUATION IS :</h3>
now shifted to 5 units left
therefore,
x=-4
hope it helps you mate thanks for the question and if possible please mark it as brainliest
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
you will need 8 pages for 400 words.
Step-by-step explanation:
250/5=50 (divided 250 with 5 and got 50)
Then I took 400 and divided it by 50 and got 8. (400/50=8)
I hope this helps!
Use the slope-intercept y=mx+b to find slope
Slope=m
M=3
Answer:
DF = 14
Step-by-step explanation:
Andrew was wrong in the assumption that DE = EF
Segments of tangents to a circle from the same external point are congruent
That is
EF = FG = 8
Then
DF = DE + EF = 6 + 8 = 14
