There no solution sorry man
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).




Subtract 160 from both sides.

Divide by –20, we get

f = 2.50
Substitute f = 2.5 in equation (3), we get


b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
a+b=350 => a=350 - b
3a + 5b = 1450
3(350-b)+b=1450
1050-3b+5b=1450
2b=400
b=200
a=150
Answer:
ox=-7
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x
=
4
,
−
7
Basically, the question is asking, what will happen if we increase 9 by 30%?
first, what is 30% of 9?

So, the increase will be by 2.7 days,
So the total amount will be 9+2.7=11.7 - this is the correct answer.