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ss7ja [257]
3 years ago
13

I’ll give you brainiest if you answer correctly! I need help

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0

Answer:

y= -3/11x + 13

Step-by-step explanation:

hope this helps ( my cousins helped me) :))

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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the s
Korvikt [17]

Answer:

37.59 nautical miles

Explanation:

Distance = Speed x Time

The speed of the first ship = 12 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =12\times1.5 \\ =18\text{ miles} \end{gathered}

The speed of the second ship = 22 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =22\times1.5 \\ =33\text{ miles} \end{gathered}

The diagram representing the ship's path is drawn and attached below:

The angle at port = 90 degrees.

The triangle is a right triangle.

Using Pythagorean Theorem:

\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}

The two ships are 37.59 nautical miles apart after 1.5 hours.

8 0
1 year ago
Brainiest answer to whoever is correct
Fittoniya [83]
3 cm because the radius is 1.5 cm and the diameter is the radius times 2
6 0
3 years ago
Read 2 more answers
URGENT! CINE SE PRICEPE LA MATEMATICĂ. [CLASA A 8-A]
kiruha [24]
The answer is yes but its could be false or 6:00
7 0
3 years ago
Please help!<br> Thanks<br> BRIANLIEST OF 2 PPL ANSWER
vlada-n [284]

Answer:

PS = 7

k = 9

Step-by-step explanation:

RS = PQ                   Given

3x  - 7 = x - 1            Substitute algebraic terms. Subtract x from both sides

3x-x - 7 = x - 1 - x    Combine

2x - 7 = - 1                Add 7 to both sides.

2x - 7+7 = -1+7         Combine

2x = 6                      Divide by 2

2x/2 = 6/2

x = 3

Length of PS = x - 1 + x + 3x - 7

Length of PS = 5x - 8

Length of PS = 5*3 - 8

Length of PS = 7

=========================

f(x) = k - x^2

x = 2

f(x) = 5  is the given point

5 = k - x^2      Substitute for x^2

5 = k - 2^2      Expand

5 = k - 4          Add 4 to both sides.

5+4=k-4+4      Combine

k = 9

8 0
3 years ago
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