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gogolik [260]
2 years ago
15

1. Fill in the chart

Mathematics
1 answer:
Murljashka [212]2 years ago
5 0

Answer:

See answers in bold

Step-by-step explanation:

Words  Expression

The Value of the Expression

a. 50 times the sum of 64 and 36 ... 50 x (64+36) = 50x (100) = 5000

50 x 64 + 36 )

5000

b. Divide the difference between  1,200 and 700 by 5 ...(1200-700) / 5 = 500/5 = 100

(1,200 - 700): 5

100

C. The sum of 3 fifteens and 17  fifteens ... \frac{3}{15} + \frac{17}{15} = \frac{20}{15} = \frac{4}{3}

45 + 255

d. 15 times the sum of 14 and 6 ... 15 x (14 + 6) = 15 (20) = 300

e.

10 x (250 +45) ...10 times the sum of 250 and 45

f.

(560 + 440) x 14... 14 times the sum of 560 and 440

Hope this helps

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Answer:

7892 = 7900

472 = 500

Step-by-step explanation:

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What is the result when 8x^3+16x2+24x+27/2x+3
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The answer is 4x^2+2x+9

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A car loses 15% of its original value each year. After one year, a car has a value of $13,600. What is the original value of the
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Help! open the attachment below!
gregori [183]

Answer:

yes it is

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                                            Y=perimeter 12/18

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2 years ago
The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

3 0
1 year ago
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