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den301095 [7]
3 years ago
11

There are 3/4 as many boys as girls in a class of 5th graders if there are 35 students in the class how many are girls?

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0
Writing an equation is the easiest way to figure this out.
b = boys, g = girlsb = 3/4g35 students = g + b35 = g + 3/4g35 = 7/4g35/7/4 = g20 girls35 - 20 = b or 3/4(35) = b15 boys
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A loan of $5000 is made by Citizens State bank at a simple interest rate of 7.25%. Calculate the simple interest owed and the to
solniwko [45]

Answer:

bite my wrist

Step-by-step explanation:

4 0
2 years ago
F(x) = -1/3 x + 7 determine the input that would give an output value of 2/3
-BARSIC- [3]
Ur output value is f(x).....so to do this problem u need to sub in 2/3 for f(x) and solve for the input value which is x

f(x) = -1/3x + 7
2/3 = -1/3x + 7 ...multiply everything by 3
2 = -x + 21
2 - 21 = - x
- 19 = -x
19 = x <== ur output

7 0
3 years ago
Read 2 more answers
Plz do number 11. its 5th grade math!​
Dmitry [639]
This is division!!
Our answer is ninety six (96)

Have a wonderful weekend
Brooke
8 0
3 years ago
The circle below is centered at the point (-1,3) and has a radius of length 4
Snowcat [4.5K]
(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point

(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
6 0
3 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
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