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Dominik [7]
3 years ago
5

A line passing through the points (-3,1) and (-2,t) has a slope equal to 2. Find the value of t.

Mathematics
2 answers:
Setler [38]3 years ago
7 0

Step-by-step explanation:

BRAINLY FREE POINTS JSJJSJJ

Kamila [148]3 years ago
3 0
T=3
(1-t)/(-3- -2)
1-t=-2
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If J is between H and K and HJ = 3(x + 2), JK = 3x -4 and KH = 44. What is the value of HJ?
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KH = 3(x + 2) + <span>3x - 4
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6x = 42
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HJ = 27</span>
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Thanks for the free points hope you find your awnser!
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Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
4 years ago
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