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Veseljchak [2.6K]
3 years ago
12

Zhang Lei spent $20.00 during his last outing at the bowling alley. This included a one time shoe rental fee of $3.50. He spent

the rest of the money on bowling a number of games. If it took Zhang Lei 45 minutes to bowl each game and he spent 2 hours and 15 minutes bowling, how much did it cost per game?
Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer: The cost per game is $5.5

Step-by-step explanation:

Zhang Lei spent $20.00 during his last outing at the bowling alley. There is a one time shoe rental fee of $3.50. He spent the rest of the money on bowling a number of games.

This means that amount paid for x number of games = 20 - 3.5 = $16.5

If it took Zhang Lei 45 minutes to bowl each game and he spent 2 hours and 15 minutes bowling, total time spent in minutes is 120+ 15 = 135 minutes. Therefore, the number of games is played is 135/45 = 3

If the total number of games played cost 16.5, therefore, the cost per game will be 16.5/3 = $5.5

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IRINA_888 [86]
Answer: 80%

Explanation:
From the provided graph, read the Relative Cumulative Frequency as 0.8 (or 80%) which corresponds to a GPA of 3.5.
This number represents all GPAs lower than 3.5.

3 0
3 years ago
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Find an n^th degree polynomial with real coefficients satisfying the given conditions. n = 3; -2 and 2 i are zeros; f(-1) = 15.
Ira Lisetskai [31]
So, n = 3, is a 3rd degree polynomial, roots are -2 and 2i

well 2i is a complex root, or imaginary, and complex root never come all by their lonesome, their sister is always with them, the conjugate, so if 0+2i is there, 0-2i is there too

so, the roots are -2, 2i, -2i

now... \bf \begin{cases}
x=-2\implies x+2=0\implies &(x+2)=0\\
x=2i\implies x-2i=0\implies &(x-2i)=0\\
x=-2i\implies x+2i=0\implies &(x+2i)=0
\end{cases}
\\\\\\
(x+2)\underline{(x-2i)(x+2i)}=0\\\\
-----------------------------\\\\
\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
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(x+2)[x^2-(2i)^2]=0\implies (x+2)[x^2-(2^2i^2)]=0
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(x+2)[x^2-(4\cdot -1)]=0\implies (x+2)(x^2+4)=0
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x^3+2x^2+4x+8=0

now, if we check f(-1), we end up with 5, not 15
hmmm

so, how to turn our 5 to 15? well, 3*5, thus

\bf 3(x^3+2x^2+4x+8)=f(x)\implies 3(5)=f(-1)\implies 15=f(-1)

usually, when we get the roots, or zeros, if any common factor that is a constant is about, they get in a division with 0 and get tossed, and aren't part of the roots, thus, we can simply add one, in this case, the common factor of 3, to make the 5 turn to 15
6 0
3 years ago
64 + {40 ÷(4 - 7 + 8)} - 10 solve this clearly​
slega [8]

Answer:

62

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction

Step-by-step explanation:

<u>Step 1: Define expression</u>

64 + [40 ÷ (4 - 7 + 8)] - 10

<u>Step 2: Evaluate</u>

  1. Brackets - Parenthesis - Subtract:          64 + [40 ÷ (-3 + 8)] - 10
  2. Brackets - Parenthesis - Add:                 64 + [40 ÷ 5] - 10
  3. Brackets - Divide:                                    64 + 8 - 10
  4. Add:                                                          72 - 10
  5. Subtract:                                                   62

And we have our final answer!

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liq [111]

Answer:

A repeating decimal or recurring decimal is decimal representation of a number whose digits are periodic (repeating its values at regular intervals) and the infinitely repeated portion is not zero.

Step-by-step explanation:

8 0
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Answer:

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-10(5) + 6 = -44

-50 + 6 = -44

-44 = -44

3 0
3 years ago
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