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Veseljchak [2.6K]
4 years ago
12

Zhang Lei spent $20.00 during his last outing at the bowling alley. This included a one time shoe rental fee of $3.50. He spent

the rest of the money on bowling a number of games. If it took Zhang Lei 45 minutes to bowl each game and he spent 2 hours and 15 minutes bowling, how much did it cost per game?
Mathematics
1 answer:
Afina-wow [57]4 years ago
4 0

Answer: The cost per game is $5.5

Step-by-step explanation:

Zhang Lei spent $20.00 during his last outing at the bowling alley. There is a one time shoe rental fee of $3.50. He spent the rest of the money on bowling a number of games.

This means that amount paid for x number of games = 20 - 3.5 = $16.5

If it took Zhang Lei 45 minutes to bowl each game and he spent 2 hours and 15 minutes bowling, total time spent in minutes is 120+ 15 = 135 minutes. Therefore, the number of games is played is 135/45 = 3

If the total number of games played cost 16.5, therefore, the cost per game will be 16.5/3 = $5.5

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Answer:

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Step-by-step explanation:

let the smaller integer be "a" and the larger be "b"

Then 2b = 3a -15              ........................equ 1

but they are consecutive integers, b= a+1 ; substitute b into equ 1,thus,

2(a+1) = 3a - 15

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collect like terms,

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b = 17+1

b=18.

The integers are 17,18

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3 years ago
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But for scientific notation we will enter decimal after two place in reverse direction.For this we will also multiply number by 10^2.

So number will be 4.81 * 10^{11} *10^2 = 4.81 * 10^{13}

So fourth option is correct.


4 0
3 years ago
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If Store B sells 12 bottles for $3.50... What is the price for 1 bottle at Store B?
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