find the range of the function f(x) = 4x - 1 for the domain {-1, 0, 1, 2, 3}. {-5, -3, 0, 7, 11} {-5, -4, -3, -2, -1} {-11, -7,
Papessa [141]
Range = {4(-1) - 1, 4(0) - 1, 4(1) - 1, 4(2) - 1, 4(3) - 1} = {-4 - 1, 0 - 1, 4 - 1, 8 - 1, 12 - 1} = {-5, -1, 3, 7, 11}
Yes it would be the opposite for example -12 it would be 12 and then 13 would stay 13
Answer:x2 355b. Hhgguyuy
Step-by-step explanation:
I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
Answer:
205-160=<em>d</em>
Step-by-step explanation: