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3 years ago

Qual o resultado da equação 12÷(6+2-(3+3))

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

Answer:

I think it is 11.5 and in a fraction 11 1/2

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Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

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3 years ago

How many milligrams is equal to 85 grams?

myrzilka [38]

85,000 milligrams is equal to 85 grams! :)

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3 years ago

Read 2 more answers

How do I subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 ?

SVETLANKA909090 [29]

$-2m^2+4mn-6n^2$

1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²

$\begin{gathered} 2m^{2}+6mn+2n^{2}-(4m^{2}+2mn+8n^2)_{} \\ 2m^2+6mn+2n^2-4m^2-2mn-8n^2 \\ -2m^2+4mn-6n^2 \end{gathered}$

2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.

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1 year ago

Find the measure of the indicated angle. Round to the nearest degree.

slava [35]

Answer:

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

Adj = 14

Hyp = 26

∠X

so use

CAH

Cos(X) = 14/26

X = arcCos(14/26)

X = 57.421°

X = 57.4 ° ( rounded to nearest 10th )

∠X

Hyp = 46

Opp = 12

use SOH

Sin(x) = 12/46

X = arcSin(12/46)

X = 15.121°

X = 15.1 ° ( rounded to nearest 10th )

∠X

Adj = 29

Opp = 24

use TOA

Tan(x) = 29 / 24

X = arcTan( 29 /24)

X = 50.389

X = 50.4 ° ( rounded to nearest 10th )

∠X

Adj = 22

Opp = 6

use TOA agian

Tan(x) = 6 / 22

X = arcTan(6/22)

X = 5.194

X = 5.2 ° ( rounded to the nearest 10th )

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3 years ago

I will give Brainly points

slamgirl [31]

Answer:

you cant see the whole graph in the photo or the question

4 0

3 years ago

Qual o resultado da equação 12÷(6+2-(3+3))​

Qual o resultado da equação 12÷(6+2-(3+3))