Answer:
∠F = 42° to the nearest degree
Step-by-step explanation:
In this question, we are asked to calculate the value of the angle.
Kindly note that since one of the angles we are dealing with in the triangle is 90°, this means that the triangle is a right-angled triangle
Please check attachment for the diagrammatic representation of the triangle
From the diagram, we can identify that the EF is the hypotenuse and the length FG is the adjacent. Thus , the appropriate trigonometric identity to use is the cosine
mathematically;
Cosine of an angle = length of adjacent/length of hypotenuse

F = 42.07
∠F = 42° to the nearest degree
Answer:
B
Step-by-step explanation:
4 or greater: 1/2 (4,5,6)
4 or smaller: 2/3 (1,2,3,4)
1/2 * 2/3 = 2/6
2/6 = 1/3
1/3 = 0.333
Answer:
The zeros are

Step-by-step explanation:
We have been given the equation x^4-6x^2-7x-6=0
Use rational root theorem, we have






Again factor using the rational root test, we get

Using the zero product rule, we have

Therefore, the zeros are

Answer:
Where is it I don't see it?
Step-by-step explanation: