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Radda [10]
3 years ago
5

= 2 у when x = 21 y=3* + 20

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer:

Step-by-step explanation:

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You walk an average of 3.2 miles per hour on the way to school and at an average of 4 miles per hour on the way home the total w
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The answer to this question is:
You walk an average of 3.2 miles per hour on the way to school and at an average of 4 miles per hour on the way home the total walking time is 18 minutes how far away is the school Round your answer to the nearest hundredth of a mile
<span>.53 mi 
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3 years ago
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Determine whether the forces in the pair are pulling at right angles to each other.
prohojiy [21]

Answer:

C) 3.0

Step-by-step explanation:

Let the length of the other side be x.

Using Pythagoras theorem for right-angled triangle,

4.2^2=2.9^2+x^2

or,x^2=4.2^2-2.9^2

or,x^2=9.23

or,x=√9.23=3.0 units

7 0
3 years ago
to go to the dog beach, it costs $3 plus $2 per dog. write an equation that shows this situation, where "x" represents the numbe
bixtya [17]
The equation representing this situation would be 3 + 2x = c, where c is the total cost.

To find the cost to bring 12 dogs, you will replace the x with the number 12.

3 + 2 x 12 = 27

The cost would be $27.
8 0
3 years ago
Last week bananas costed 0.79 per pound this week they cost 0.89 per pound
kirza4 [7]

Answer:

10 cent increase

Step-by-step explanation:

0.89

<u>-0.79</u>

0.10

or 7.89%

8 0
2 years ago
If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

Q_1 = \frac{15 + 1}{4}

Q_1 = \frac{16}{4}

Q_1 = 4th

Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

Q_3 = 12th

So, we have:

Q_1 = 4th

Q_3 = 12th

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

U = Q_3 + 1.5 \times (Q_3 - Q_1)

So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0
3 years ago
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