Answer: 
Step-by-step explanation:
The acceleration
of the satellite can be calculated by the following equation:

Where:
is the final speed of the satellite
is the initial speed of the satellite (it was "stationary" before the release)
is the time
Isolating
:


Finally:

"They have different slopes but the same y-intercept, so they have one solution" is the statement which best describes the two lines.
Answer: Option D
<u>Step-by-step explanation:</u>
Given equations:


As we know that the slope intercept form of a line is
y = m x + c
So, from equation 1 and equation 2 we can see that


So, from the above expressions, we can say that both lines have different slopes but have same y – intercept with one common solution when x = 0.
Answer:
148
Step-by-step explanation:
148