Step-by-step explanation:
16 data points.
the mean value is the sum of all data points divided by the number of data points :
13896/16 = 868.5
the median is the data point with half of the other data points being smaller and the other half being bigger.
as we have an even number of data points, we need to apply the extra rule :
the median is the mean value between the 2 middle points (where one half of the other data points is smaller than these 2, and the other half is bigger than these 2).
in our case we have 138 and 240.
the mean value between these 2 and therefore the median of the list is
(138 + 240)/2 = 378/2 = 189
Answer:
The answer is 243 I believe
Step-by-step explanation:
Multiply 27 times 6, once you get the product of that, multimply that by 3. Once you have done all of that multiply that by 1/2 or 0.5
Answer:
You get paid $9 per hour
Step-by-step explanation:
Answer:
Area of the image rectangle = 4(Area of the original rectangle)
Step-by-step explanation:
Length of the rectangle given in the graph = 4 units
Width of the rectangle = 2 units
Area of the rectangle = Length × Width
= 4 × 2
= 8 square units
Since, scale factor = 
2 = 
Length of the image rectangle = 2(4)
= 8 units
Similarly, width of the image rectangle = 2(2)
= 4 units
Area of the image rectangle = 8 × 4
Area of the image = Area of the original × 4
Area of the image = 4(Area of the original)
Area of the image rectangle = 4(Area of the original rectangle)
Answer:
Both expressions are equal. One expression cannot be greater than the others.
Step-by-step explanation:
The given expressions are:
A: (x + y)
B: (x) + (y)
<h3>Let x = a and y = b</h3>
A: (a+b) = a+b
B: (a)+(b) = a+b
<h3>Let x = -a and y = -b</h3>
A: (-a+ (-b)) = -a-b
B: (-a)+(-b) = -a-b
<h3 /><h3>Let x = a and y = -b</h3>
A: (a+(-b)) = a-b
B: (a)+(-b) = a-b
<h3 /><h3>Let x = -a and y = b</h3>
A: ((-a)+b) = -a+b
B: (-a)+(b) = -a+b
We can see the pattern that both expressions are always equal to each other, no matter what value of x and y you plug in. One expression cannot be greater than the other
