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3 years ago

I need help with math. i attached a pic

Mathematics

2 answers:

wel3 years ago

7 0

Answer:

Step-by-step explanation:

This one is quite easy. If you look angle M is slightly obtuse which means that it can't be A or B but it is to small to be D.

Ad libitum [116K]3 years ago

4 0

Answer:

B 68

Step-by-step explanation:

MNPQ is a parallelogram

opposite angles are equal.

6x -2 = 4x + 36

6x = 4x + 36 + 2

6x - 4x = 38

2x = 38

x = 38/2

x = 19

m∠M = 6x - 2 = 6*19 - 2 = 114 - 2 = 112

m∠M , m∠N are adjacent angles

In parallelogram sum of adjacent angles is 180

m∠M + m∠N = 180

112 + m∠N = 180

m∠N = 180 - 112

m∠N = 68

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For which value of X is the row in the table of values incorrect? The function is the quadratic function Y=3/4x^2

svet-max [94.6K]

Answer:

The row with x = 2 and y = 4 is incorrect. The y value should be y = 3 when x = 2.

==============================================================

Explanation:

Fractions can be a bit of a pain, so I'm going to be converting to decimal form to help with the computation; however, I will convert the y value results to mix number form so that it matches what the table shows.

Keep in mind that 3/4 = 0.75 when you use a calculator or long division. So a number like 2.75 means 2 & 3/4 (two and three quarters)

---------------

Let's check the first row. Plug in x = 0 and it leads to...

y = (3/4)*x^2

y = (3/4)*0^2

y = (3/4)*0

y = 0.75*0

y = 0

This shows us that row 1 is correct. When x = 0, y = 0 leading to (x,y) = (0,0).

-------------

Repeat the same basic outline of steps, but now use x = 2

y = (3/4)*x^2

y = (3/4)*2^2

y = (3/4)*4

y = 0.75*4

y = 3

So instead of 4, the proper y value is y = 3 when x = 2. This means row 2 is the answer (the row that has the incorrect values).

-------------

For the sake of completeness, let's see if the third row is correct or not. Plug in x = 3

y = (3/4)*x^2

y = (3/4)*3^2

y = (3/4)*9

y = 0.75*9

y = 6.75

y = 6 & 3/4

We see that x = 3 points to y = 6 & 3/4, so we have the correct values in this row. We can cross this off the list of choices.

-------------

Finally, let's check x = 5

y = (3/4)*x^2

y = (3/4)*5^2

y = (3/4)*25

y = 0.75*25

y = 18.75

y = 18 & 3/4

We get the proper y value. So we can also cross this off the list.

5 0

2 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

36 + 120 : 12-63 What's this answer?

NeTakaya

Answer:

Step-by-step explanation:

36 + 120: 12-63

156 : 51

GCF of both sides are three. Divide both sides by three.

52:17

5 0

2 years ago

There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45

nignag [31]

Part A

f(x)=30∗0.2xandf(x)=45+3x
___________________________________________________________

Part B

f(x)=30+0.2(5)f(x)=45+3(5)
Neighborhood A and neighborhood B both have 60 houses after 5 years

___________________________________________________________

Part C

1 year
A=36
B=48

2 years
A=42
B=51

3 years
A=48
B=54

4 years
A = 54
B = 57

5 years
A = 60
B= 60

5 0

2 years ago

Read 2 more answers

What quadrant is (6,-8) in

Oliga [24]

Answer:

quadrant 2

Step-by-step explanation:

because its a + and - and only quadrant 2 can have it

3 0

2 years ago