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Mrac [35]
3 years ago
13

The sphere's radius is half the radius of the hemisphere. How does the volume of this hemisphere compare with the volume of the

sphere?
A.. It depends on the value of r
B. It is equal to the volume of the sphere.
C. It is less than the volume of the sphere.
D. It is greater than the volume of the sphere.
Mathematics
2 answers:
seraphim [82]3 years ago
8 0

Answer: D It is greater than the volume of the sphere

sertanlavr [38]3 years ago
4 0
B..I think, it is equal to the volume of the sphere

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Enter the sum of numbers as a product of their GCF. 75 + 30 The sum of the numbers as a product of their GCF is
Oksanka [162]

Answer: 75+30 = 15 x 7

Step-by-step explanation:

The given expression is 75+30 (=105) which defines the sum of 75 and 30.

Prime factorization of 75 and 30 are as below:

75 = 5 x 5 x 3

30 = 5 x 3 x 2

GCD (75,30) = 5x 3 = 15  [Note: GCD = Greatest common divisor]

Consider 75+30 = (15 x 5) + (15 x 2)   [75 = 15 x 5 and 30= 15 x 2]

=  15 (5+2)   [taking 15 as common ]

= 15 x (7)

(=105)

So,  75+30 which is sum of the numbers and it is expressed as 15 x 7 which  a product of their GCF.

7 0
3 years ago
A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

5 0
3 years ago
Is ab perpendicular to cd ? Explain.
Afina-wow [57]
We know that
if two lines are perpendicular
then
the slopes 
m1*m2=-1

step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3

step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4

step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
 AB is not perpendicular to CD
4 0
3 years ago
V^2=12^2+2(-6)(9) answer please i am waitind
il63 [147K]

Answer:

V = 6 or V = -6

Step-by-step explanation:

Solve for V over the real numbers:

V^2 = 12^2 - 6 2 9

12^2 + 2 (-6) 9 = 36:

V^2 = 36

Take the square root of both sides:

Answer: V = 6 or V = -6

3 0
3 years ago
Read 2 more answers
E (0,3), F (1,-1), G (4, 2), H (-1,3) what's EF? And What's GH?
sergey [27]

Answer:

I'm assuming you want the distance between the two point

EF = \sqrt{17\\}

GH = \sqrt{26}

Step-by-step explanation:

7 0
3 years ago
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