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8090 [49]
2 years ago
14

The last week of a month a car dealership sold 12 cars. A new sales promotion came out the first week of the next month and the

sold 19 cars that week. What was the percent increase in sales from the last week of the previous month compared to the first week of the next month? A. 58% B. 119% C. 158% D. 175% E. 200%
Mathematics
1 answer:
Svetlanka [38]2 years ago
8 0
The answer is A. 58%
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Please ASAP help please !!! Help me anyone
worty [1.4K]

difference of squares means that both the terms are square terms. (also there must be a - symbol)

for example

y^2 - 4

square root of y^2 is y

square root of 4 is +2 as well as -2

so you would factorise it like this:

(y+2)(y-2)

1. y^4 has a square root of y^2 as y^2 × y^2 is y^4.

<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>-2 doesnt have a whole number square root so it is not a difference of squares.

2. 25 has a square root of 5. m^2 has a square root of m. n^4 has a square root of n^2. so this 25m^2n^4 is a square term.

1 has a square root of +1 and -1.

therefore, this one is a difference of squares. <u>(</u><u>5</u><u>m</u><u>n</u><u>^</u><u>2</u><u> </u><u>+</u><u>1</u><u>)</u><u> </u><u>(</u><u>5</u><u>mn^2</u><u> </u><u>-</u><u>1</u><u>)</u>

3. p^8 has a square root of p^4. q^4 has a square root of +q^2 and -q^2)

so it is a difference of squares. <u>(</u><u>p</u><u>^</u><u>4</u><u>+</u><u>q</u><u>^</u><u>2</u><u>)</u><u>(</u><u>p</u><u>^</u><u>4</u><u> </u><u>-</u><u>q</u><u>^</u><u>2</u><u>)</u>

4. 16x^2 is a square term as irs square root is 4x.

<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>24 is not a square term.

therefore, it is not a difference of squares.

6 0
3 years ago
Help help help help please business
Margaret [11]

Answer:

x = 35°

Step-by-step explanation:

These are corresponding angles. When a transversal crosses 2 parallel lines, 4 angles are created at each intersection, and each pair of corresponding angles between those are congruent.

These angles are congruent, so you can set them equal to each other:

2x+20=3x-15

Then, just solve for x:

20=x-15\\35=x\\x=35

You can check that by plugging it back into both:

2x+20=3x-15\\2(35)+20=3(35)-15\\70+20=105-15\\90=90

3 0
2 years ago
Read 2 more answers
A​ person's rectangular dog pen for his dog must have an area of 200 square feet.​ Also, the length must be 12 feet longer than
kherson [118]

Answer:

width = 9.36 ft

length = 21.36 ft

Step-by-step explanation:

Let the width be x ft long. Then it follows that the length will be (x+12) ft long.

To calculate the area would then be

x(x+12) = 200

xx^{2} +12x=200x^{2} +12x-200=0

x = 9.36 ft or x = -21.36 ft

We take the positive answer. So the dimensions are

width = 9.36 ft

length =  9.36 + 12 = 21.36 ft

6 0
2 years ago
2 2/3× 4 1/5 help me plzzzzz!!!
Rus_ich [418]
First let's multiply the whole numbers 2 and 4. Obviously that is 8. Now let's put aside the whole number and multiply fractions.

2/3 x 1/5 is equal to 2x1/3x5 so it's 2/15 which is already in simplest form. 

So your final answer is 8 and 2/15 :)

If this was helpful would you mind marking mine as brainliest please? It helps me rank up a lot!
8 0
3 years ago
A coffee shop covers it coffee cups for holiday seasons. Their cups are cylindrical, have a 2 inch radius, and a height of 6 inc
slega [8]

Answer:

Surface area of square box cover is 4x12=48in^{2}

Step-by-step explanation:

Given cylindrical cup have 2 in of radius and height of 6 in.

It is said that we need to cover the cup leaving top and bottom of cup.

To find how much material to cover:

After covering the cup, square box will be formed around the cup.

As shown in figure, Top view of square cup and box.

One face of box has length of diameter of cup = 2 in and height of box as height of cup = 6 in

Therefore, Area of one face of square box is length x height = 2 x 6 =12 in^{2}

Since, Box having 4 faces

Surface area of square box cover = 4 x area of one face of box

= 4x12=48in^{2}

8 0
3 years ago
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